Saturday, December 31, 2011

Monday, November 28, 2011

Tuesday, November 22, 2011

World tour finals

If Nadal wins his next two matches in 2 sets and Fish beats Federer in 2 sets. Federer/Tsonga/Fish will be 1-2. Tiebreak: set won/loss ratio. Federer 2-5, Tsonga 3-4, Fish 3-4. Federer is eliminated because the 2nd tiebreak(set ratio) creates an inferior player. Then the tiebreak between Fish and Tsonga is decided by head to head.


rule

Tiebreak

If three (3) players are tied, then:
i) If three (3) players each have one (1) win, a player having played less than
all three (3) matches is automatically eliminated and the player advancing
to the single elimination competition is the winner of the match-up of the
two (2) players tied with 1-2 records; or
ii) Highest percentage of sets won; or
iii) Highest percentage of games won; or
iv) The player positions on the South African Airways ATP Rankings as of the
Monday after the last ATP World Tour tournament of the calendar year.
v) If (i), (ii), (iii) or (iv) produce one (1) superior player (first place), or one (1)
inferior player (third place), and the two (2) remaining players are tied, the
tie between those two (2) players shall be broken by head-to-head record.
Comment 1: 1 player has 3 wins and the other 3 players have 1 win. Of the

Sunday, May 15, 2011

WORLD T FINAL RULE

IV. WORLD CHAMPIONSHIPS
4.01 Barclays ATP World Tour Finals - Singles


B.Entries
1) Selection List. The selection list for the event shall be:
a) The top seven (7) players in the South African Airways ATP Rankings as of the
Monday after the last ATP World Tour tournament of the calendar year; followed
by
b) Up to two (2) Grand Slam winners of that year, in order of their positions, positioned
between eight (8) and twenty (20) in the South African Airways ATP
Rankings as of that Monday; followed by
c) Players
positioned eight (8) and below in the South African Airways ATP
Rankings as of that Monday.
2)



source: atp rulebook